(x-3)^2+(2x-2)^2-68=0

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Solution for (x-3)^2+(2x-2)^2-68=0 equation: 



(x-3)^2+(2x-2)^2-68=0

We move all terms containing x to the left, all other terms to the right

(x-3)^2+(2x-2)^2=68

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